Question

Find the equation of a line in slope-intercept form that passes through the points (-2, 20) and (3, -10).

Answer 1

Simple...

you have: (-2,20) and (3,-10,)

Using
`( y_(1)- y_(2) )/( x_(1)- x_(2) )` to find slope--->>>


`(20--10)/(-2-3) = (30)/(-5)`

=-6

m=-6

Using y=mx+b to find the equation of the line-->>>(Use any of the coordinates)

(-2,20)

20=-6(-2)+b

20=12+b

20=12+b
-12 -12

8=b

y=-6x+8

Thus, your answer.