Let
x ----> large current
y ----> smaller current
we have that
x+y=20 ------> x=20-y ------> equation 1
x=y+30 -----> equation 2
solve the system of equations
equate both equations
y+30=20-y
solve for y
2y=20-30
2y=-10
y=-5
Find out the value of x
x=20-(-5)
x=25
therefore
The value of the large current is 25 mA