Find the standard equation of the circle passing through a given point with a given center . Center (6,3) and passing through (0,-1)

asked Jan 11, 2017 188k views

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The radius of the circle is r =
$\sqrt{ (6-0)^(2) + (3-(-1))^(2) } = √(52) ;$
The standard equation of the circle is
(x-6)^(2) + (y - 3)^(2) = 52;

Eikes answered Jan 17, 2017

by Eikes

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