Question

A 55-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30. A 140-N force is applied to the box. What is the frictional force on the box?

Answer 1

161.7N

Step-by-step explanation:

Given parameters:

Mass of the box = 55kg

Coefficient of friction = 0.3

Applied force = 140N

Unknown:

Frictional force on the box = ?

Solution:

The frictional force on the box is a force that opposes the motion of the box.

To find the value of this force;

Fr = u m g

u is the coefficient of static friction

m is the mass

g is the acceleration due to gravity

So;

Fr = 0.3 x 55 x 9.8 = 161.7N