Find three consecutive odd integers, such that five more than the smallest integer is equal to 25 less than 3 times the largest number. Show work

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asked Jul 25, 2017 38.5k views

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Edsamiracle · Answer 1 · 2017-07-29T22:48:34+0000

Let x be the smallest number and y be the largest number.
3y-25-5= x
x+4=y

3(4+x)-25-5= x
12+3x-25-5= x
3x-x=-12+25+5
2x/2= 18/2.
X= 9
x+4=y
(9)+4=y
13. =y

The second number is 11.

Find three consecutive odd integers, such that five more than the smallest integer is equal to 25 less than 3 times the largest number. Show work

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