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A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

User Behelit
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2 Answers

2 votes
work done = force * distance moved (in direction of the force)

force= mass* acceleration

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J
User Founddrama
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7.6k points
3 votes

The correct answer to the question is
336.98* 10^4\ J

CALCULATION:

The acceleration of the truck is given as a =
0.0083\ m/s^2

The mass of truck is given as m = 7000 kg.

The distance travelled by the truck S =
5.8* 10^(4)\ m.

The force applied on the truck is calculated as -

Force F = mass × acceleration

=
7000\ kg* 0.0083\ m/s^2

= 58.1 N.

We are asked to calculate the work done .

The work done by a body is calculated as -

W =
\vec F.\vec S

=
FScos\theta

Here,
\theta is the angle between force and displacement.

If
\theta=0^(0), then W = FS

Hence, the work done by the truck W = FS

=
58.1\ N* 5.8* 10^(4)\ m

=
336.98* 10^4\ J

Here, J ( joule ) is the unit of work.

User Bindiya Patoliya
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8.9k points