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A rectangle is drawn so that the width is 3 feet shorter than the length. The area of the rectangle is 70 square feet. Find the length of the rectangle.

1 Answer

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Answer:

The length of the rectangle (l) = 10 cm

The width of the rectangle (w) = 7 cm

Explanation:

Step(i):-

Let 'x' be the length of the rectangle

Given that the width is 3 feet shorter than the length

The width of the rectangle = x -3

Area of the rectangle = length × width

Step(ii):-

Area of the rectangle = length × width

= x ( x-3)

Given that the area of the rectangle = 70 square feet

x ( x-3) = 70

⇒ x² - 3x - 70 =0

⇒ x² - 10 x + 7 x - 70 =0

⇒ x (x -10) +7( x-10) =0

⇒ ( x+7) ( x-10) = 0

⇒ x =-7 and x=10

Final answer:-

we choose x=10

The length of the rectangle (l) = 10 cm

The width of the rectangle (w) = 7 cm

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