6u4+41u2+70 Final result : (3u2 + 10) • (2u2 + 7) Step by step solution :Step 1 :Skip Ad
Equation at the end of step 1 : ((6 • (u4)) + 41u2) + 70 Step 2 :Equation at the end of step 2 : ((2•3u4) + 41u2) + 70 Step 3 :Trying to factor by splitting the middle term 3.1 Factoring 6u4+41u2+70
The first term is, 6u4 its coefficient is 6 .
The middle term is, +41u2 its coefficient is 41 .
The last term, "the constant", is +70
Step-1 : Multiply the coefficient of the first term by the constant 6 • 70 = 420
Step-2 : Find two factors of 420 whose sum equals the coefficient of the middle term, which is 41 .
-420 + -1 = -421 -210 + -2 = -212 -140 + -3 = -143 -105 + -4 = -109 -84 + -5 = -89 -70 + -6 = -76 -60 + -7 = -67 -42 + -10 = -52 -35 + -12 = -47 -30 + -14 = -44 -28 + -15 = -43 -21 + -20 = -41 -20 + -21 = -41 -15 + -28 = -43 -14 + -30 = -44 -12 + -35 = -47 -10 + -42 = -52 -7 + -60 = -67 -6 + -70 = -76 -5 + -84 = -89 -4 + -105 = -109 -3 + -140 = -143 -2 + -210 = -212 -1 + -420 = -421 1 + 420 = 421 2 + 210 = 212 3 + 140 = 143 4 + 105 = 109 5 + 84 = 89 6 + 70 = 76 7 + 60 = 67 10 + 42 = 52 12 + 35 = 47 14 + 30 = 44 15 + 28 = 43 20 + 21 = 41