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A family took a trip. they spent $90.71 for gasoline, $153.00 on meals, $197.00 on amusements, and $73.38 on miscellaneous expenses. how much did the trip cost? 366.88 440.71 514.09 587.47

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gasoline...........90,71
meals.............153,00
anusements...197,00
miscellaneous..73,38

total................514,09
User Bradfordrg
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Answer: The correct option is (C) $ 514.09.

Step-by-step explanation: Given that a family took a trip, where they spent $90.71 for gasoline, $153.00 on meals, $197.00 on amusements, and $73.38 on miscellaneous expenses.

We are to find the total cost of the trip.

The total cost of the trip will be given by the sum of all the expenses that the family done in the trip.

Therefore, the total cost of the trip is


T_c=\$(90.71+153.00+197.00+73.38)\\\\\Rightarrow T_c=\$514.09.

Thus, the trip cost $514.09.

Option (C) is CORRECT.

User Mark Ryan Orosa
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