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Show from first principles that the derivative of a constant is zero

User Jeremywoertink
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Given

To show from first principles that the derivative of a constant is zero .

Step-by-step explanation

We have to prove that from the first principle the derivative of a constant is zero.

To prove :

If f(x) =c, for some constant c, then f'(x) = 0.

Proof :

Suppose f(x) = c for some constant c.

Then the derivative of f(x) can be determined as


\begin{gathered} f^(\prime)(x)=\lim_(h\to0)(f(x+h)-f(x))/(h) \\ f^(\prime)(x)=(c-c)/(h) \\ f^(\prime)(x)=0 \end{gathered}

Hence proved.

User Alphy
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