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Multiple polynomial and monomial 9r^3(r^2 - 3r +5)

User Agila
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1 Answer

22 votes
22 votes

Let's determine the product of the following equation:


\text{ 9r}^3(r^2\text{ - 3r + 5)}

We get,


\text{ 9r}^3(r^2\text{ - 3r + 5)}
\text{ 9r}^3(r^2)+\text{ 9r}^3(\text{-3r) }+\text{ 9r}^3(\text{5)}
\text{ 9r}^{3\text{ + 2}}+(9)(-3)r^{3\text{ + 1}}+(9)(5)r^3
\text{ 9r}^5+(-27)r^4+(45)r^3
\text{ 9r}^5-27r^4+45r^3

Therefore, the answer is:


\text{ 9r}^5-27r^4+45r^3

User Idnovate
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