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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

User Viviana
by
7.6k points

2 Answers

2 votes
Determinante:
x....y....1
-3..11...1
1...-3....1

11x+y+9+3x+3y-11 = 0
11x+3x+y+3y+9-11 = 0
14x+4y-2 = 0

4y = -14x + 2
y = (-14x + 2)/4
y = (-7x+1)/2
User Rohan Seth
by
8.2k points
5 votes
(-3, 11)+(1, -3)=(-2, 8)
User Stefano Sambruna
by
8.3k points
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