Final answer:
The quadratic equation -4x^2-3x+2=0 can be solved using the quadratic formula, yielding two possible solutions for x.
Step-by-step explanation:
To solve the quadratic equation -4x^2-3x+2=0 using the quadratic formula, we first identify the coefficients: a = -4, b = -3, and c = 2. The quadratic formula is x = (-b ± √(b²-4ac))/(2a). Substituting the coefficients into the formula, we get:
x = (3 ± √((-3)²-4(-4)(2)))/(2(-4))
x = (3 ± √(9+32))/(2(-4))
x = (3 ± √(41))/(-8)
Therefore, we have two potential solutions for x:
x = (3 + √(41))/(-8) or x = (3 - √(41))/(-8)
These are the two possible values for x using the quadratic formula.