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A converging lens has a focal length of 0.38 m. If an object is placed at 0.79 m from the lens, where will its image be located?

User Damjad
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1 Answer

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23 votes

Answer:

Step-by-step explanation:

We would apply the formula,

1/u + 1/v = 1/f

where

u is the object distance

v is the image distance

f is the focal length

From the information given,

f = 0.38

u = 0.79

Thus,

1/0.79 + 1/u = 1/0.38

1/v = 1/0.38 - 1/0.79

v = 1/[1/0.38 - 1/0.79]

v = 0.73

The image would be 0.73m on the opposite side of the object

User Lkristjansen
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