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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(4)] 2.
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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(4)] 2.

User Brian Frost
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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)] 2

User Candela
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I think the function of f(x) is X^2 + 1 and I think you're looking for (f(4))^2. Assuming this, you plug 4 into the f function so 4^2 +1= 17 and 17^2 is 289.
User Indivara
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