Question

I am very confused but I tried I don't I know if I am right!

Answer 1

Step 1

Tree diagram for total possible outcomes.

Step 2

Total possible outcome = { 1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}

Total possible outcome = 12

Required outcome = {3H , 6H } = 2

Step 3

`\begin{gathered} \text{Probability of m ultiple of 3 and head= }\frac{n\text{ umber of required outcome}}{n\text{ umber of possible outcome}} \\ \\ =\text{ }(2)/(12) \\ =\text{ }(1)/(6) \end{gathered}`