Question

Given the function f defined by f(x)=3x^2-4. which statement is true

1. f(0)= 0
2. f(-2)= f(2)
3. f(2) + f(5) = f(7)
4. f(5) x f(2) = f(10)

PLEASE EXPLAIN

Answer 1

a;lsdkfj;alksjfka;l

ok so

here i am
woot

f(2) basically means substituting the value of x in the equation with a number 2
f(5) would mean subs x with a 5
and so on and so on until
i think u'll get it :)

Answer 2

we will proceed to solve each case to determine the solution

we have

`f(x)=3x^2-4`

case 1) f(0)= 0

For
`x=0`

Find the value of f(x)

`f(0)=3*0^2-4`

`f(0)=-4`

so

`f(0)\\eq 0`

therefore

the statement case 1) is false

case 2) f(-2)= f(2)

For
`x=-2`

Find the value of f(x)

`f(-2)=3*(-2)^2-4`

`f(-2)=8`

For
`x=2`

Find the value of f(x)

`f(2)=3*(2)^2-4`

`f(2)=8`

so

`f(-2)=f(2)`

therefore

the statement case 2) is true

case 3) f(2) + f(5) = f(7)

For
`x=2`

Find the value of f(x)

`f(2)=3*(2)^2-4`

`f(2)=8`

For
`x=5`

Find the value of f(x)

`f(5)=3*(5)^2-4`

`f(5)=71`

For
`x=7`

Find the value of f(x)

`f(7)=3*(7)^2-4`

`f(7)=143`

so

`f(2)+f(5)\\eq f(7)`

therefore

the statement case 3) is false

case 4) f(5) x f(2) = f(10)

For
`x=5`

Find the value of f(x)

`f(5)=3*(5)^2-4`

`f(5)=71`

For
`x=2`

Find the value of f(x)

`f(2)=3*(2)^2-4`

`f(2)=8`

For
`x=10`

Find the value of f(x)

`f(10)=3*(10)^2-4`

`f(10)=296`

so

`f(5)*f(2)\\eq f(10)`

therefore

the statement case 4) is false

The answer is

`f(-2)= f(2)`