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Determine an appropriate solution to solve xdy/dx=yln(xy)

User Tamtom
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1 Answer

1 vote

x(\mathrm dy)/(\mathrm dx)=y\ln(xy)

Let
v=xy, so that
(\mathrm dv)/(\mathrm dx)=y+x(\mathrm dy)/(\mathrm dx), or
(\mathrm dv)/(\mathrm dx)-\frac vx=x(\mathrm dy)/(\mathrm dx). Then you have


(\mathrm dv)/(\mathrm dx)-\frac vx=\frac vx\ln v

(\mathrm dv)/(v(\ln v+1))=\frac{\mathrm dx}x

Integrate both sides to get


\ln|\ln v+1|=\ln|x|+C

\ln v+1=Cx

v=e^(Cx-1)

then back-substitute to find the solution for
y.


xy=e^(Cx-1)\implies y=\frac{e^(Cx-1)}x
User Alex Tartan
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