Question

What is the equation, in point-slope form, for a line that goes through (8, −4)) and has a slope of −56 ?

1)y+4=−56(x−8)

2)y+4=−56(x+8)

3)y−4=−56(x−8)

4)y−4=−56(x+8)

Answer 1

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Hope this helped out! :)

Answer 2

y - y1 = m(x - x1)
slope(m) = -56
(8,-4)...x1 = 8 and y1 = -4
now we sub...pay close attention to ur signs
y - (-4) = -56(x - 8)....not finished yet
y + 4 = -56(x - 8) <===