Question

What is the equation in point-slope form of a line that passes through the points (−4, −1) and (5, 7) ?

1)y+1=8/9(x+4)

2)y+1=8/7(x+4)

3)y+4=9/8(x+1)

4)y−1=8/9(x−4)

Answer 1

(-4,-1)(5,7)
slope = (7 - (-1) / (5 - (-4) = (7 + 1) / (5 + 4) = 8/9

y - y1 = m(x - x1)
slope(m) = 8/9
(-4,-1)...x1 = -4 and y1 = -1
now we sub
y - (-1) = 8/9(x - (-4) =
y + 1 = 8/9(x + 4) <==