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Solutions of lead(II) nitrate and potassium iodide were combined in a test tube. Write a formula equation for the reaction. Which of the possible products is the precipitate, and how do you know?

User Benjamin BALET
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1 Answer

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Answer

Equation: Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

The PbI₂ is the formed solid precipitate.

Step-by-step explanation

The balanced equation for the reaction of solutions of lead(II) nitrate and potassium iodide in the test tube is given below:

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

The reaction is an example of a double displacement reaction.

The PbI₂ is the formed solid precipitate.

The complete ionic equation for the reaction is:

Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → 2K⁺(aq) + 2NO₃⁻(aq) + PbI₂(s)

The spectator ions are NO₃⁻ and K⁺

While the net ionic equation for the reaction is:

Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

User Danish Farhaj
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