Question

A spring on the produce scale at the farmers market has a spring constant of 5.2 N/m. A giant bag of apples is hung from the spring and the spring stretches 0.32m. What is the elastic potential energy stored in the spring?

Answer 1

PE= 0.5*K*X^2

where:
PE= potential energy
K= Spring Constant
X= extension

0.5*5.2*(0.32^2)
=0.27J