Question

Consider the following function.q(x) = -(x + 1)^2 - 6Step 3 of 4: Find two points on the graph of the parabola other than the vertex and x-intercepts.

Answer 1

(-2, - 7), (1, -10)

Step-by-step explanation:

Two find any two points, we put in our desired values of x and solve to get the output

Let us choose x = - 2. Putting this value into the equation gives

`q(-2)=-(-2+1)^2-6`

simplifying the above gives

`\begin{gathered} q(-2)=-1(-1)^2-6 \\ q(-2)=-1-6 \\ q(-2)=-7 \end{gathered}`

Hence, we have the point (-2, -7).

Now we choose x = 1 and put it into the equation:

`q(1)=-1(1+1)^2-6`

`q(1)=-4-6`
`q(1)=-10`

Hence, we have the point ( 1, -10).

To summarise, the two points we got are:

`(1,-10),(-2,-7)`