Question

How many grams of sugar are required to make 336.6g of a 23.48%w/w solution ?Be sure to include correct Units and SigFigs

Answer 1

79.03 g of sugar.

Step-by-step explanation:

First, let's see the mass percent (% w/w) formula:

`Percent\text{ by mass=}\frac{mass\text{ }of\text{ }solute}{mas\text{s of solution}}\cdot100\%.`

The problem is telling us that we have a solution with a mass of 336.6 g and its percent by mass is 23.48 % w/w and they are asking us to find the mass of sugar, which in this case, sugar is the solute.

To answer this problem, we have to solve for 'mass of solute' and replace the given data, as follows:

`\begin{gathered} Mass\text{ of solute=}\frac{percent\text{ by mass}\cdot mass\text{ of solution}}{100\%}, \\ \\ Mass\text{ of solute=}\frac{23.48\%\cdot336.6\text{ g}}{100\%}, \\ \\ Mass\text{ of solute=79.03 g.} \end{gathered}`

The answer would be that we require 79.03 g of sugar.