Question

a buffer solution contains .120 M acetic acid and .150 M sodium acetatea. how many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?

Answer 1

How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?

We calculate it as follows:

moles of acetic acid = .120 mol/L (.050 L ) = 0.006 mol
moles of sodium acetate = 0.150 mol/L (0.050 L) = 0.008 mol

Hope this answers the question. Have a nice day.