Question

How many moles are in 68 grams of copper (ll) hydroxide, Cu(OH)2

Answer 1

Molar mass Cu(OH)2 => 97.561 g/mol

Therefore:

1 mole Cu(OH)2 ------------ 97.561 g
? moles Cu(OH)2 ----------- 68 g

= 68 x 1 / 97.561

= 68 / 97.561

= 0.696 moles of Cu(OH)2

Answer 2

Answer: The moles of copper (I) hydroxide are 0.70 moles.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

We are given:

Given mass of copper (I) hydroxide = 68 g

Molar mass of copper (I) hydroxide = 97.6 g/mol

Putting values in above equation, we get:

`\text{Moles of copper (I) hydroxide}=(68g)/(97.6g/mol)=0.70mol`

Hence, the moles of copper (I) hydroxide are 0.70 moles.