Answer: B. 1.2 m/s
Step-by-step explanation:
First we would find the velocity with which red car and blue car move when they combine after first collision.
Using law of conservation of momentum,
Initial momentum = final momentum
Mass of red Car, Mr = 225 kg
Mass of blue car, Mb = 180 kg
Mass of green car, Mg = 150 kg
Initial velocity of red car, Ur = 3.0 m/s
Initial velocity of blue car, Ub = 0
Initial velocity of green car, Ug = 0
collision 1:
Mr Ur + Mb Ub = (Mr+Mb) V
where, V is the final velocity with which red and blue car moves.
225 × 3 + 0 = (225 + 180 ) V
⇒ V = 675/ 405 = 1.67 kg.m/s
collision 2:
These cars collide with the green car. Let the final velocity with which the three cars move together after collision: V'
(Mr+Mb) V + Mg Ug = (Mr+Mb+Mg) V'
675 + 0 = 555 V'
⇒V' = 1.2 m/s
Thus, the correct option is B.