Question

How many moles of propane (C3H8) are in a 7.00-L tank at 20.0°C and 5.45 atm of pressure?

Answer 1

By the claperyron equation:

T = 20.0ºC + 273.15 => 293.15 K

R = 0.082 atm

Therefore:

P x V = n x R x T

5.45 x 7.00 = n x 0.082 x 293.15

38.15 = n x 24.0383

n = 38.15 / 24.0383

n = 1.587 moles of C3H8