One of the laws of exponents is expressed as
a^b / a^c = a^(b - c)
By applying this law to the given expression, it becoms
50/25 * s^(1 - 0) * t^(2 - 3)
= 2* s^0 * t^- 1
s^0 = 1
Thus, it becomes
2t^-1
Another law is expressed as
a^(- 1) = 1/a
Thus, t ^ - 1 = 1/t
The final expression is
2 * 1/t
= 2/t