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Find the equation of the line that is parallel y= 2x+10 and passes through the point (6,-4)

Find the equation of the line that is parallel y= 2x+10 and passes through the point-example-1
User Bsarrazin
by
7.6k points

1 Answer

11 votes

Answer:

The equation of the parallel line to the given line

y = 2 x - 16

Explanation:

Step(i):-

Given equation of the straight line y = 2 x +10

2x - y + 10 =0

The equation of the parallel line to the given line is

a x + by + k=0

The equation of the parallel line to the given line is

2x - y + k=0

Step(ii):-

Given point ( 6,-4)

The equation of the parallel line to the given line is

2x - y + k=0

This line passing through the point ( 6,-4)

2(6) - (-4)+ k=0

12 + 4 +k =0

16 + k=0

k = -16

Final answer:-

The equation of the parallel line to the given line

y = 2 x - 16

User Piyush Katariya
by
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