Question

Pleaaase help me!!!!

For questions 1-2 find the x- and y-intercept of the line

1. -10x +5y= 40
a. x- intercept is 5; y-intercept is -10
b. x-intercept is 8; y-intercept is -4
c. x-intercept id -10; y-intercept is 5
d. x-intercept is -4; y-intercept is 8

2. 5x + 4y=80
a. x-intercept is 4; y-intercept is 5
b. x-intercept is 20; y-intercept is 16
c. x-intercept is 5; y-intercept is 4
d. x-intercept is 16; y-intercept is 20

Answer 1

If you happen to be looking for the answers for the quick check then it is 1.D 2.D 3.B 4.A 5.D

Explanation:

Answer 2

For 1, the answer is D because:
-10x + 5y = 40
add 10x to both sides
5y = 10x + 40
divide by 5
y = 2x + 8, In the equation y=mx+b, b is the y-intercept so then 8 is your y-intercept. To find the x-intercept you just plug in 0 for y and then solve for x:
0 = 2x + 8
subtract 8 from both sides
-8 = 2x
divide by 2
-4 = x, so the x-intercept is -4.

For 2, the answer is D because:
5x + 4y = 80
subtract 5x from each side
4y = -5x + 80
divide by 4
y = -5/4x + 20, In the equation y=mx+b, b is the y-intercept so then 20 is your y-intercept. To find the x-intercept you just plug in 0 for y and then solve for x:
0 = -5/4x + 20
subtract 20 from each side
-20 = -5/4x
multiply each side by 4
-80 = -5x
divide by -5
16 = x.