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Use a sum or difference identity to find an exact value sin(15 degrees)

2 Answers

7 votes

Answer:

its B on edge

Explanation:

sqrt6-sqrt2 / 4

User Mike D Sutton
by
8.6k points
4 votes

The solution would be like this for this specific problem:

30 + 15 = 45

sin 45 = sin(30+15) = sin30cos15 + cos30sin15

cos 45 = cos(30+15) = cos30cos15 - sin30sin15

sin45 = cos45 (= sqrt(2)/2)

sin30 = 1/2 and cos30 = sqrt(3)/2

1/2 cos15 + sqrt(3)/2 sin15 = sqrt(3)/2 cos15 - 1/2 sin15

(sqrt(3)/2 + 1/2)sin15 = (sqrt(3)/2 - 1/2)cos15

sin15 = (sqrt(3)/2 - 1/2)/(sqrt(3)/2 + 1/2) * cos15

sin15 = (1/2 *(sqrt(3) - 1))/(1/2 * (sqrt(3) + 1) * cos15

sin15 = (sqrt(3) - 1)/(sqrt(3) +1) * cos15

cos15 = sin30/(2sin15) = 1/2/(2sin15) = 1/(4sin15)

sin15 = (sqrt(3) - 1)/(sqrt(3) + 1) * (1/(4sin15))

4(sin15)^2 = (sqrt(3) - 1)/(sqrt(3) + 1)

4(sin15)^2 = (sqrt(3) - 1)^2 / ((sqrt(3) + 1)(sqrt(3) - 1))

4(sin15)^2 = (3 - 2sqrt(3) +1) / (3 - 1) = (4 - 2sqrt(3)) / 2 = 2 - sqrt(3)

sin15 = sqrt((2 - sqrt(3))/4)

sin15 = sqrt(2 - sqrt(3)) / 2

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

User Gary Willoughby
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