So the question is the least number of passengers needed to make the fare for each less than $80
n would be the number of passengers.
Then n-80=the number of passengers over 80
2(n-80)= amount each passenger's fare is reduced,
155-2(n-80)= the reduced fare per passenger.
So, the reduced fare per passenger is less than $80:
155-2(n-80)<80
Solving the inequality:
155-2n+160<80
-2n+315<80
-2n<80-315
-2n<-235
n>-235/-2
n>235/2
The number of passengers must be an integer, so
At least 118 passengers must go.