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" A bowl of soup at 200Á F. is placed in a room of constant temperature of 60Á F. The temperature T of the soup t minutes after it is placed in the room is given by T(t) = 60 + 140 e _ 0.075 t Find the
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" A bowl of soup at 200Á F. is placed in a room of constant temperature of 60Á F. The

temperature T of the soup t minutes after it is placed in the room is given by
T(t) = 60 + 140 e
_ 0.075 t
Find the temperature of the soup 12 minutes after it is placed in the room. (Round to the nearest
degree.)
"

User Tgmerritt
by
6.1k points

1 Answer

1 vote
T(t)=60+140e−0.075t T(12)=60+140e−0.075∗12 T(12)=60+140e−0.9 T(12)=60+140(0.4065696597)
=116.84
So the temperature will be approximately 117 degrees
User Rahul Tank
by
6.3k points
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