Question

Right the balanced equation then find the number of moles in the mass of chlorine C L2 required to react with 10 g of sodium metal and a to produce sodium chloride NaCl

Answer 1

D. 2Na + Cl₂ → 2NaCl and 0.2175 moles or 7.71 g

Step-by-step explanation

Given:

Mass of sodium that reacts = 10 g

What to find:

To write the balanced equation then find the number of moles in the mass of chlorine Cl₂ required to react with 10 g of sodium.

Step-by-step solution:

Step 1: Write the balanced chemical equation between the sodium metal and chlorines.

2Na + Cl₂ → 2NaCl

Step 2: Convert the mass of sodium metal given to moles using the mole formula.

Molar mass of Na = 23.0 g/mol

`Moles=\frac{Mass}{Molar\text{ }mass}=\frac{10\text{ }g}{23.0\text{ }g\text{/}mol}=0.4348\text{ }mol\text{ }Na`

Step 3: Determine the moles of Cl₂ using the moles of Na in step 2 and mole ratio from the equation in step 1.

From step 1; 2 mole of Na requires 1 mole of Cl₂

So, 0.4348 moles of Na will require

`\frac{0.4348\text{ }mol\text{ }Na}{2\text{ }mol\text{ }Na}*1\text{ }mol\text{ }Cl_2=0.2175\text{ }mol\text{ }Cl_2`

Step 4: Convert the moles of Cl₂ in step 3 to mass using the mole formula.

Molar mass of Cl = 34.453 g/mol

`\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ \Rightarrow Mass=Moles* Molar\text{ }mass \\ \\ Mass=0.2175\text{ }mol*35.453\text{ }g\text{/}mol=7.71\text{ }g \end{gathered}`

Therefore, the correct answer is:

D. 2Na + Cl₂ → 2NaCl and 0.2175 moles or 7.71 g