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The coordinates of the vertices of a polygon are (−2,1), (−3,3), (−1,5), (2,4), and (2,1).

What is the perimeter of the polygon to the nearest tenth of a unit?

15.2 units

15.9 units

16. 5 units

18.8 units

User Anuj Kumar
by
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2 Answers

1 vote

Answer:

15.2 units

Step-by-step explanation:

The coordinates of the vertices of a polygon are (−2,1), (−3,3), (−1,5), (2,4), and-example-1
User Jeremy Green
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0 votes

Answer: The correct option is A. The perimeter of the polygon is 15.2 units.

Step-by-step explanation:

The perimeter of a shape is the sum of its all sides.

Let the vertices of the polygon be ABCDE.


\text{perimeter}=AB+BC+CD+DE+AD

Use distance formula to find the length of sides.


D=√((x_2-x_1)^2+(y_2-y_1)^2)


AB=√((3-1)^2+(-3+2)^2)=√(4+1)=√(5)


BC=√((5-3)^2+(-1+3)^2)=√(4+4)=√(8)


CD=√((4-5)^2+(2+1)^2)=√(1+9)=√(10)


DE=√((1-4)^2+(2-2)^2)=√(9+0)=3


AE=√((1-1)^2+(-2-2)^2)=√(0+16)=4

So, the length of sides are
√(5),√(10),√(8), 3,4


\text{perimeter}=√(5)+ √(10)+ √(8)+ 3+4


\text{perimeter}=2.23+3.16+2.83+7


\text{perimeter}=15.22

When we Approx 15.22 to nearest tenth, we get 15.2.

Therefore, A is the correct option.

The coordinates of the vertices of a polygon are (−2,1), (−3,3), (−1,5), (2,4), and-example-1
User Louis W
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8.5k points

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