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In Calvin cycle, 1 molecule of glucose is formed from :1 6CO2 + 18ATP + 3ONADPH2 6CO2 + 18ATP + 12NADP3 6CO2 + 30ATP + 12NADPH4 6CO2 + 12ATP

User Lakeesha
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1 Answer

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21 votes

Solution:

For a total of 6 molecules of fixed carbon dioxide, the final stoichiometry of the Calvin cycle can be summarized in the following equation:

This would represent the formation of a 6-carbon phosphate sugar molecule.

Now, the Calvin cycle uses chemical energy from ATP to combine six carbon atoms from six CO2 molecules with 12 hydrogens from NADPH to produce one molecule of glucose. So that, we can conclude that the correct answer is:

In Calvin cycle, 1 molecule of glucose is formed from :1 6CO2 + 18ATP + 3ONADPH2 6CO-example-1
In Calvin cycle, 1 molecule of glucose is formed from :1 6CO2 + 18ATP + 3ONADPH2 6CO-example-2
User Thattyson
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