We are given two points on a straight line
A = (5, -6)
B = (4, 5)
Let find the slope first
Slope = Rise / run
Rise = y2 - y1
Run = x2 - x1
x1 = 5, y1 = -6 x2 = 4 and y2 = 5
Rise = 5 - (-6)
Rise = 5 + 6
Rise = 11
Run = 4 - 5
Run = -1
We have ratio 3 to 4
The means that point P divides line AB into the ratio of 3:4
P= 3 / 3+4
P = 3/7
The run is given as -1
Then the horizontal distance between A and p
3/7 x -1
-3/7 - 5
-38/7
For rise, we have 11
The distance between A and P
11 x 3/7
33/7 + 6
75 /7
The points are -38/7 and 75/7
(-38/7, 75/7)
The answer is (-38/7, 75/7)