Final answer:
The oxidation number of iron (Fe) in the compound Fe(NO3)2 is +2. This is determined by knowing that the nitrate ion has a nitrogen atom with a +5 oxidation state, and since each nitrate ion has a -1 charge and there are two of them, the iron must balance the charge with a +2 oxidation number.
Step-by-step explanation:
The student asked how to determine the oxidation numbers of all elements in Fe(NO3)2. In this compound, iron (Fe) can have more than one oxidation state. However, we know that the nitrate ion (NO3¯) has a nitrogen atom with a +5 oxidation state because oxygen typically has an oxidation number of -2. Since the nitrate ion is a polyatomic ion with a charge of -1 and there are three oxygen atoms, the algebraic expression for the nitrogen oxidation number is x + 3(-2) = -1, solving for x gives us +5, which is nitrogen's oxidation number.
For Fe(NO3)2, we need to find the oxidation number of Fe. Since there are two nitrate ions (each with a net charge of -1) attached to the Fe, the combined charge of the nitrates is -2. To balance this, the Fe must have a +2 oxidation number so that the overall charge of the compound is neutral. The algebra for this is Fe2+ + 2(NO3¯) = 0, indicating that the iron oxidation number is +2.