Question

A certain shade of blue has a frequency of 7.02 × 1014 Hz. What is the energy of exactly one photon of this light?

Answer 1

The energy (E) per photon is expressed by Planck's equation: E = hf, where f is
the frequency and h is Planck's constant, experimentally determined to be
6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency
and obtain E = hf = (6.625 * 10**-34)(7.0 * 10**14) = 46.375 * 10**-20 joule
or in standard notation, E = 4.6375 * 10**-19 joule per photon.

Hope this answers your question.Sorry if I calculated wrong.

Answer 2

Answer : The energy of one photon is
`4.65* 10^(-19)J`

Explanation : Given,

Frequency of blue light =
`7.02* 10^(14)Hz=7.02* 10^(14)s^(-1)`

Formula used :

`E=h\\u`

where,

`\\u` = frequency of blue light

h = Planck's constant =
`6.626* 10^(-34)Js`

E = energy of one photon = ?

Now put all the given values in the above formula, we get:

`E=(6.626* 10^(-34)Js)* (7.02* 10^(14)s^(-1))`

`E=4.65* 10^(-19)J`

Therefore, the energy of one photon is
`4.65* 10^(-19)J`