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When exiting the highway, a 1100-kg car is traveling at 22 m/s. the car's kinetic energy decreases by 1.4×105j the exit speed limit is 35 mi/h.?

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I think you want to determine the exit speed?

You have to determine how much velocity was decreased by calculating it from the kinetic energy.


KE = (1)/(2) mv^(2)


1.4 x 10^(5)= (1)/(2) (1100) v^(2)


v^(2) =254.55


v = 15.95 m/s

So the velocity reduces by 15.95 m/s. Subtracting this to the initial velocity: 22 - 15.95 = 6.05 m/s.

So, the final speed was 6.05 m/s.

I hope I was able to help :)
User Tapefreak
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