Question

When exiting the highway, a 1100-kg car is traveling at 22 m/s. the car's kinetic energy decreases by 1.4×105j the exit speed limit is 35 mi/h.?

Answer 1

I think you want to determine the exit speed?

You have to determine how much velocity was decreased by calculating it from the kinetic energy.


`KE = (1)/(2) mv^(2)`


`1.4 x 10^(5)= (1)/(2) (1100) v^(2)`


`v^(2) =254.55`


`v = 15.95 m/s`

So the velocity reduces by 15.95 m/s. Subtracting this to the initial velocity: 22 - 15.95 = 6.05 m/s.

So, the final speed was 6.05 m/s.

I hope I was able to help :)