Question

The quadratic equation y = –6x2 + 100x – 180 models the store’s daily profit, y, for selling soccer balls at x dollars. The quadratic equation y = –4x2 + 80x – 150 models the store’s daily profit, y, for selling footballs at x dollars. Use a graphing calculator to find the intersection point(s) of the graphs, and explain what they mean in the context of the problem

Answer 1

see explanation

Explanation:

The quadratic equation models the store’s daily profit, y, for selling soccer balls at x dollars.The quadratic equation models the store’s daily profit, y, for selling footballs at x dollars.Now we are supposed to find the intersection point(s) of the graphs using graphing calculatorRefer the attached graph. -- Green line -- Purple line So, from the graph we can see there are two intersection points :(8.333,236.667)(2.053,0)So, from solution (8.333,236.667) we depict that at x = 8.333 dollars the store's daily profit y = 236.667 for selling football or soccer ball.From solution (2.053,0)we depict that at x = 0 dollars the store's daily profit y = 2.053 for selling football or soccer ball.

Answer 2

Explanation:

The quadratic equation
`y = -6x^2 + 100x - 180` models the store’s daily profit, y, for selling soccer balls at x dollars.

The quadratic equation
`y = -4x^2 + 80x - 150` models the store’s daily profit, y, for selling footballs at x dollars.

Now we are supposed to find the intersection point(s) of the graphs using graphing calculator

Refer the attached graph.

`y = -6x^2 + 100x - 180` -- Green line

`y = -4x^2 + 80x - 150` -- Purple line

So, from the graph we can see there are two intersection points :

(8.333,236.667)

(2.053,0)

So, from solution (8.333,236.667) we depict that at x = 8.333 dollars the store's daily profit y = 236.667 for selling football or soccer ball.

From solution (2.053,0)we depict that at x = 0 dollars the store's daily profit y = 2.053 for selling football or soccer ball.