196k views
3 votes
How do I graph the quadratic y=4(x-2)^2-1 ?

1 Answer

5 votes
Let's find the vertex first, h=-2 <0 so the graph move the right 2 units and k=1 >0 the graph shift up 1 unit. The vertex is (2,1)
Now we find some point of the graph . ( at least 3 (include the vertex))
the normal point when the vertex is (0,0) are (1,1) and (-1,1). Now take those points plus the vertex like
for the point ( 1,1) plus (2,1) : (1+2,1+1) = (3,2) is the first point.
another point is (-1+2,1+1)=(1,2) .


User Mohd
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories