Question

Jennifer and Michael walk with an average velocity of 0.89 m/s eastward if it takes them 43 minutes to walk to the store what is their displacement

Answer 1

2296.2 m

Step-by-step explanation

The average velocity is the quotient between the displacement and time:

`v_(avg)=(\Delta x)/(\Delta t)`

Solving for displacement:

`\Delta x=v_{\text{avg}}\cdot\Delta t`

We know that they walk at an average velocity of 0.89 m/s and it took them 43 minutes to get to the store. First we have to either convert the time from minutes to seconds or convert the velocity from m/s to m per minute. Let's convert the time, because it is a bit faster:

`\begin{gathered} 1\min =60s \\ t=43\min =43\min \cdot(60s)/(1\min )=2580s \end{gathered}`

Now we can multiply the velocity and time, because their units are consistent:

`\Delta x=0.89(m)/(s)\cdot2580s=2296.2m`

Their displacement to the store was 2296.2 meters