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25 votes
25 votes
Evaluate h(-8) for h(x)=1/4x² + 7x

User Mike Taverne
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1 Answer

26 votes
26 votes

Answer:

h(-8) = -40

Step-by-step explanation:

Given the function:


h(x)=(1)/(4)x^2+7x

To evaluate the value of h(-8), we substitute -8 for x in h(x).


\begin{gathered} h(-8)=(1)/(4)(-8)^2+7(-8) \\ =((1)/(4)*64)-56 \\ =16-56 \\ =-40 \end{gathered}

User Kombuwa
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