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If the point (-1/2, y) lies on the line whose equation is 2x - 3y = 6, what is the value of y?

If the point (-1/2, y) lies on the line whose equation is 2x - 3y = 6, what is the value of y?
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If the point (-1/2, y) lies on the line whose equation is 2x - 3y = 6, what is the value of y?

User Chantz
by
8.7k points

1 Answer

1 vote
2x - 3y = 6, replace x = -1/2

2(-1/2) -3y = 6
-1 - 3y = 6
-3y = 7
y = -7/3
User Jim K
by
8.3k points
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