Question

4. What is the length of NO?N2x + 50/4x + 20

Answer 1

The length of NO is 80.

Given:

The length of the side ML is 2x+50.

The length of the side NO is 4x+20.

The objective is to find the length of NO.

Since the given figure resembles the shape of a rhombus, the opposite sides are equal.

Then, the value of x can be calculated as,

`\begin{gathered} ML=NO \\ 2x+50=4x+20 \\ 2x-4x=20-50 \\ -2x=-30 \\ x=-(30)/(-2) \\ x=15 \end{gathered}`

Now substitute the value of x in the equation of NO.

`\begin{gathered} NO=4x+20 \\ =4(15)+20 \\ =60+20 \\ =80 \end{gathered}`

Hence, the length of NO is 80.