Question

A carton of eggs contains 7 good eggs and 3 cracked eggs. If 4 eggs are selectedat random fromthe carton, what is the probability that 3 eggs are good and one egg is cracked?

Answer 1

`P=(1)/(7)`

Explanation:

The probability is represented by the following equation:

`P(A)=\frac{Number\text{ of favorable outcomes}}{\text{ Total number of possible outcome}}`

If the total of eggs is 10. 7 are good eggs and 3 are cracked eggs. Then, the probability of selecting randomly 4 eggs and 3 of them are good and one egg is cracked:

Probability of Two Events Occurring Together: Independent

Just multiply the probability of the first event by the second.

`\begin{gathered} P=(3)/(7)*(1)/(3) \\ P=(1)/(7) \end{gathered}`