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The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent?

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The average rate of change of distance over the time interval
3 ≤ t ≤ 6 represents the coin's average velocity over that interval.
User JoeBigToe
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