Question

]Find the value of n such that x^2-10x+n is a perfect square trinomial.

A) 50
B) 25
C) -5
D)100

Answer 1

I hope this helps you



x.x-2.5.x+n


(x-5)(x-5)


(x-5)^2


n= -5

Answer 2

x^2 - 10x + [10/2]^2 = x^2 -10x +5^2 = (x -5)^2 = x^2 -10x + 25

Then n = 25.

Answer: option B) 25